SOLVED:Find the average value of the function f(x) = sin^2 x cos^3 x on the interval [-π, π] .
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SOLVED:Find the average value of the function f(x) = sin^2 x cos^3 x on the interval [-π, π] .
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SOLVED: Find the point(s) at which the given function equals its average value on the given interval. Show all work that justifies your answer: You may use the formula "df(x) = 3 -x; [-3, 6]
SOLVED: Find the point(s) at which the given function equals its average value on the given interval. Show all work that justifies your answer: You may use the formula "df(x) = 3 -x; [-3, 6]
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SOLVED:In Exercises 15-18, find the average value of the function on the interval without integrating, by appealing to the geometry of the region between the graph and the x -axis. f ( x ) = { x 4 , - 4 ≤ x ≤ - 1 , - x 2 , - 1 < x ≤ 2 , . on [ - 4,2 ] y = x 4 / ( 3 )/( 2 ) y = - x 2 - 4 x
SOLVED:In Exercises 15-18, find the average value of the function on the interval without integrating, by appealing to the geometry of the region between the graph and the x -axis. f ( x ) = { x 4 , - 4 ≤ x ≤ - 1 , - x 2 , - 1 < x ≤ 2 , . on [ - 4,2 ] y = x 4 / ( 3 )/( 2 ) y = - x 2 - 4 x
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SOLVED: Find the point(s) at which the given function equals its average value on the given interval. Show all work that justifies your answer: You may use the formula "df(x) = 3 -x; [-3, 6]
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SOLVED:In Exercises 15-18, find the average value of the function on the interval without integrating, by appealing to the geometry of the region between the graph and the x -axis. f ( x ) = { x 4 , - 4 ≤ x ≤ - 1 , - x 2 , - 1 < x ≤ 2 , . on [ - 4,2 ] y = x 4 / ( 3 )/( 2 ) y = - x 2 - 4 x
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